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## Prove that e^pi > pi^e , Inequality

You can use natural logarithm to prove this equality. You will get

Let the f(x)=x/e & g(x)=lnx . f(x) is a line and g(x) is a hyperbole. The graphs of this functions touch each other at point x=e and f(x) always bigger than g(x) except point x=e.

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Categories: Inequality
e, inequality, Natural logarithm, pi

You should use

instead of

to parse .