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Prove that e^pi > pi^e , Inequality

November 25, 2011 1 comment

e^{\pi} > {\pi}^e

You can use natural logarithm to prove this equality. You will get

\pi > e \cdot \ln \pi

\pi/e > \ln \pi

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Categories: Inequality Tags: , , ,

Inequality of arithmetic and geometric means

September 21, 2011 Leave a comment
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